42cos(x) - 28sin(7x + pi/2)
-28?
D'oh. No, 42 - 28 ... uhhh. *gets out calculator* 14?
![[User Picture]](http://l-userpic.livejournal.com/9624370/1571) | From: evan 2007-07-19 09:24 pm (UTC)
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I answered it below.
I got a real easy one...
p(x) = x^2 + 2x + 1 find the real roots of the polynomial
hillarious though!
I got -3 * (-4) - (-2) = ?
See, I didn't need to take Calculus after all!
that should be the test to prove you're Asian.
That's better than a password ;)
7*6*cos(12pi) - 4*7*sin(14pi + pi/2) = 42-28 = 14
![[User Picture]](http://l-userpic.livejournal.com/34474992/3171) | From: mart 2007-07-19 06:50 pm (UTC)
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Quick! Write an OCR system that can grok mathematical notation!
Quick! Write an evaluator for one of the output formats from this! It's still loaded with style, but at least it's text.
![[User Picture]](http://l-userpic.livejournal.com/39022159/14) | From: erik 2007-07-19 07:08 pm (UTC)
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The answer is 7 you guys. I just did it in my head.
![[User Picture]](http://l-userpic.livejournal.com/9624370/1571) | From: evan 2007-07-19 07:20 pm (UTC)
possibly embarrassing myself here | (Link)
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I forget calculus syntax. Is that asking you to just evaluate at x=2pi? In that case, the sin is +1 and the cos is -1 at that point, so it's just 7 - 4 = 3.
![[User Picture]](http://l-userpic.livejournal.com/39022159/14) | From: erik 2007-07-19 07:54 pm (UTC)
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You mean I was only off by 4?! Not bad!
![[User Picture]](http://l-userpic.livejournal.com/4273510/813044) | From: zarex 2007-07-19 08:22 pm (UTC)
Re: possibly embarrassing myself here | (Link)
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You have to take the derivative first, then evaluate it at the point x=2pi. Anyway, sin(N*2pi)=0, cos(N*2pi+pi/2)=0.
![[User Picture]](http://l-userpic.livejournal.com/9624370/1571) | From: evan 2007-07-19 09:22 pm (UTC)
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I meant "evaluate the derivative", and "the sin is +1" I meant "the derivative at that point is +1". Nikolas did it more thoroughly below.
![[User Picture]](http://l-userpic.livejournal.com/4273510/813044) | From: zarex 2007-07-19 09:45 pm (UTC)
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He messed up too. :) Must be a lot of programmers hanging around here, and not enough engineers.
From: nibot 2007-07-19 10:18 pm (UTC)
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I think you both forgot to apply the chain rule. The derivative of 7Sin[6x] is 42 Cos[6x], etc.
![[User Picture]](http://l-userpic.livejournal.com/38603346/857000) | From: nikolasco 2007-07-19 08:56 pm (UTC)
Spelling it out ... | (Link)
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1. Differentiate 7*cos(6x) + 4*-sin(7x + π/2)
2. Evaluate 7*cos(6*2*π) + 4*-sin(7*2*π + π/2) those in love with calculators can skip to the last line = 7*cos(0) + 4*-sin(π/2) = 7*1 + 4*-1 = 3
![[User Picture]](http://l-userpic.livejournal.com/9624370/1571) | From: evan 2007-07-19 09:23 pm (UTC)
Re: Spelling it out ... | (Link)
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Alternatively, what I did was visualize what the derivatives at those well-known points are: the sin is maximally sloping upwards (+1) and the cos maximally downwards (-1), which got me to your second-to-last step without computing any derivatives directly. :)
![[User Picture]](http://l-userpic.livejournal.com/4273510/813044) | From: zarex 2007-07-19 09:44 pm (UTC)
Re: Spelling it out ... | (Link)
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You missed a factor on the derivative. D[ sin(ax) ] = a*cos(ax) . Remember D[ sin(u) ] = cos(u)du . See my solution above.
From: nibot 2007-07-19 10:15 pm (UTC)
you forgot the chain rule | (Link)
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zarex has the correct answer above, 14.
![[User Picture]](http://l-userpic.livejournal.com/9624370/1571) | From: evan 2007-07-19 10:23 pm (UTC)
Re: Spelling it out ... | (Link)
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Haha, we suck. Chain rule?
![[User Picture]](http://l-userpic.livejournal.com/38603346/857000) | From: nikolasco 2007-07-19 10:59 pm (UTC)
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I'm mostly amused that I probably would have correctly written a program that did it (numeric or symbolic), but I screwed up evaluating it by hand immediately. Anywho, the chain rule is one of the basic few that they teach circa first week of calc. (When writing a symbolic program I would have double-checked the list by eye and test cases. For the numeric, I'd probably just use a three-point evaluation) Corrected(?) version: shose in love with fancy calculators or Mathemtica and it's ilk can just write the answer1. Differentiate 7*6*cos(x) + 4*7*-sin(x + π/2) 2. Evaluate 7*6*cos(2*π) + 4*7*-sin(2*π + π/2) those in love with scientific calculators can skip to the last line= 7*6*cos(2*π) + 4*7*-sin(3π/2) = 7*6*cos(0) + 4*7*-sin(π/2) those in love with four-function calculators can skip to the last line= 7*6*1 + 4*7*-1 = 42 - 28 = 14
There was a time when I could actually do the math. Now it's like a bad dream. uffff.
I took 2 years of AP Calc in high school, and now, I hardly remember a lick of it!
Cincinnati State Tech. a looong time ago :)
Yeah, yeah, it's funny and all, but wouldn't this be pretty simple for a computer, and pretty damn hard for most humans.
![[User Picture]](http://l-userpic.livejournal.com/9624370/1571) | From: evan 2007-07-19 09:23 pm (UTC)
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I think it may have been intentionally constructed to be easy. See my comments above.
Except for the fact that you have to OCR and parse a math equation correctly.
so if you know the answer does that mean you're a computer or human? i think humans would get the wrong answer. i know i would.
Either I'm not a human or I'm totally blonde... -_-"
i always knew i wasnt a real person...
cause computers are terrible at math
So, if you get the correct answer, you must be automated.
![[User Picture]](http://l-userpic.livejournal.com/43751323/32029) | From: ossie 2007-07-20 09:17 am (UTC)
after a few reloads | (Link)
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I got the question
-6+7-1=?
so I am human
![[User Picture]](http://l-userpic.livejournal.com/59338292/8575621) | From: alenja 2007-07-20 10:21 am (UTC)
great | (Link)
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so..now I have a lot of variants who I am- martian, animal, machine... but i'm quite sure that i'm not human!
wtf?  |